x^2=4+3x-8

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Solution for x^2=4+3x-8 equation: 



x^2=4+3x-8

We move all terms to the left:

x^2-(4+3x-8)=0

We add all the numbers together, and all the variables

x^2-(3x-4)=0

We get rid of parentheses

x^2-3x+4=0

a = 1; b = -3; c = +4;
Δ = b2-4ac
Δ = -32-4·1·4
Δ = -7
Delta is less than zero, so there is no solution for the equation

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